show that x=1 is a root of polynomial 2xcube +3xsquare+7x-6
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if on putting x=1,the polynomial become zero,then it hence prove

it is not a zero of polynomial
it is not a zero of polynomial
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Solution :-
☆ x = 1
:- put the value of x in equation
:- 2x*3 + 3x*2 + 7x -6
= 2 (1)*3 + 3 (1)*2 + 7(1) - 6
= 2+3+7-6
= 12 - 6
= 6
Hence, Its is not the Zeros of polynomial
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
☆ x = 1
:- put the value of x in equation
:- 2x*3 + 3x*2 + 7x -6
= 2 (1)*3 + 3 (1)*2 + 7(1) - 6
= 2+3+7-6
= 12 - 6
= 6
Hence, Its is not the Zeros of polynomial
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
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