Question

Question - In the given figure,
BPD = BQD
BPC = BOC.
and
Prove that
CPD = CQD
[See Figure First]​

Answer 1

Answer:For triangles CAP and BAP,

AP = PA (common side)

∠ BAP = ∠ CAP (AD is the angle bisector of ∠ BAC)

→ ∠ BPA = ∠ CPA (as we have given ∠ BPD = ∠ CPD, ∠ BPA = 180⁰ - ∠ BPD and ∠ CPA = 180⁰ - ∠ CPD)

Hence Δ CAP congruent to Δ BAP

CP = BP (CPCT).

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