Question

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Question:-
★If a bulb is marked 220volt and 40watt. Calculate the current flowing through the bulb and it's resistance★

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Answer 1

$\large{ \bold{ \underline{ \underline{ \: Answer : \: \: \: }}}}$

$\to$ Current = 0.1818 amp

$\to$ Resistance = 1210.12 ohm

$\large{ \bold{ \underline{ \underline{ \: Explaination : \: \: \: }}}}$

Given ,

$\star \: \sf Power = 40 \: watt \\ \star \: \sf Voltage = 220 \: volt$

$\fbox{\fbox{\bold{ \: \: \sf Current \: ( I ) = \frac{Power \: ( P ) }{ \: \: Voltage \: ( V ) \: \: } \: \: }}}$

$\sf \to Current = \frac{40}{220} \\ \\ \sf \to Current = 0.1818 \: \: amp$

$\bold{ \fbox{ \fbox{ \sf Resistance \: (R) = \frac{ \: \: Voltage \: (V) }{ \: \: Current \: (I) \: \: } \: \: }}}$

$\sf Resistance = \frac{220}{0.1818} \\ \\ \sf Resistance = 1210.12 \: \: ohm$

$\therefore$ 0.1818 amp current flowing through the bulb and it's resistance is 1210.12 ohm

Answer 2

Answer:

1210.12 is your answer