Question

Question no. 10
ASAP

Answer 1

hey buddy here is your answer

by taking LCM of 520 and 468

we get 2*2*2*3*3*5*13 = 4680

now according to question we need a number which is which is divisible of 520 and 468 by adding 17

So we needs to decrease 17 for applying our condition

so = 4680-17 = 4663 ( answer )
is the smallest number in which we can add 17 and it will be divisible by both 529 and 468

hope it helps