Question

question no. 18. first

Answer 1

Given: In trapezium ABCD

ab||dc

AB = 18 cm, DC = 32 cm

and distance between AB and DC = 14 cm

> Area of trapezium ABCD = 1/2(32+18)×14

=50×7

=350

Now circles are drawn of radii 7 cm from A, b, C, D.

We know that sum of all angles of a trapezium = 360°

=area circle inside trapezium with centre ABCD = area of circle with 7 cm = TT x (7 cm)^2

=22/7×7×7

=154cm^2

hence remaining area=350-154=196cm^2