Question

Question No. 29
A three-phase, fully controlled thyristor bridge converter is used as line commutated inverter to feed 50 kW power 420 Vdc to a three-phase, 415V (line), 50Hz ac mains. Consider dc link current to
be constant. The rms current of the thyristor is​

Answer 1

Answer:

$p = v_d + i_d \\ 50 \times 1000 = 420 \times i _d \\ i_d = 119.05 \\ rms \: current \: of \: thyristor \\ = 119.05 \div 3 \\ = > 39.68a$

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Answer 2

Answer:

Step-by-step explanation:

idc=p/v

rms current= I/√3

=68.7