Math, asked by kusum72, 1 year ago

question number 20...

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Answered by SmãrtyMohït
12
Here is your solution

Let,
The terms be

a-d, a, a+d 

sum = 21

a - d + a + a + d = 21
3a = 21
a = 7...(1)

sum of squares = 165

(a - d)^2+ a^2 + (a + d)^2 = 165

3a^2+ 2d^2 = 165

3(7^2) - 165 = - 2d^2

d^2= 9

d = 3 , - 3

1st term = a = 7

2nd term = a +d = 7 +3 = 10

3rd term = a + 2d = 7+2×3=13

kusum72: can you write it in a copy and click a picture and post it....it will be more helpful..
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