Question

Question number 61 if u solve this you will be awarded 8 points..

Answer 1

i am pankaj .....sorry for wait

Answer 2

LHS = Tan^3A / ( 1+ Tan^2A) + Cot^3A / (1 + Cot^2a)

=Tan^3A / Sec^2A + Cot^3A / Cosec^2A

=(sin^3A/cos^3A) / (1 / Cos^2A) + (Cos^3A/Sin^3A) / (1 / Sin^2A)

=Sin^3A/CosA + Cos^3A/SinA

= (Sin^4A + Cos^4A) / SinA.CosA

= [ (Sin^2A + Cos^2A)^2 - 2Sin^2A.Cos^2A] / SinA.CosA

= ( 1- 2Sin^A.Cos^A)/ SinA.CosA

RHS = SecA CosecA - 2sinAcosA

=1/CosA . 1/SinA - 2SinACosA

= (1 - Sin^2A.Cos^2A) / sinAcosA

Hence LHS = RHS

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