Question of 5 marks only
Solve Q7 to Q13
SQP - 04 Maths
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hey mate,
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Question:7
Solution:
K=k×1
2k=k×2
3k=k×3
4k=k×4
5k=k×5
K is common in all.
Therefore,
The HCF of k,2k,3k,4k and 5k is k.
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Question: 10
Solution:
Sin90° / cos45° + 1/ Cosec 30°
= 1/( 1/√2 ) + 1/2
= √2 + 1/2
= ( 2√2 + 1 ) / 2
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Question : 11
Solution:
➡️The radius of circle
= 8 cm
➡️diameter
= 8×2
= 16 cm
➡️The diameter of circle
= diagonal of square
= 16 cm
➡️area of square
= (diagonal)²/2
= 16²/2
= 128 cm²
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Question 12:
Solution:
Given mode =20
repeated 15,18,20,25 three times
therefore,
lambda =20
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thanks....
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