Question

"Question14
Evaluate, 4/cot²30° + 1/sin²30° - 2cos²45° - sin²0°
Chapter6, Trigonometry, Exercise -6 ,Page number 288"

Answer 1

Hey there!
We know that,
cot30 = √3
sin30 = 1/2
cos45 = 1/√2
sin0 = 0

⇒4/cot²30° + 1/sin²30° - 2cos²45° - sin²0°
⇒4/(√3)² + 1/(1/2)² - 2 ( 1/√2)² - 0
⇒ 4/3 + 4 - 1 - 0
⇒ 4/3 + 3
⇒ 4/3 + 9/3
⇒ 13/3

4/cot²30° + 1/sin²30° - 2cos²45° - sin²0° = 13/3
Hope helped!

Answer 2

HELLO DEAR,


4/cot²30° + 1/sin²30° - 2cos²45° - sin²0°


=> 4/(√3)² + 1/(1/2)² - 2(1/√2)² - 0


=> 4/3 + 4 - 1


=> (4 + 9)/3


=> 13/3



I HOPE ITS HELP YOU DEAR,
THANKS