Question33 Three circles of radius a,b and c touch each other externally. The area of the triangle formed by joing their center is:
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given radius: a,b,c
SO USE THE AREA OF TRIANGLE 1st :-
perimeter. = a+b+c/2
s √(s-a) (s-b) (s-c) = ar of a triangle . i.e. 1/2 * b*h
SO USE THE AREA OF TRIANGLE 1st :-
perimeter. = a+b+c/2
s √(s-a) (s-b) (s-c) = ar of a triangle . i.e. 1/2 * b*h
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Vyapakgupta:
Can i get a proper solution?the equation is getting really complex?
i can send u the pic of a figure..k
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