Question

R is [ a2 + b2 + 2ab cos ]1/2

Answer 1

Answer:(r-(1/2)) 2 is (r-(1/2)) 2/2 = (r-(1/2)) 1 = r-(1/2) Now, applying the Square Root Principle to Eq. #3.2.1 we get: r-(1/2) = √ 9/4 Add 1/2 to both sides to obtain: r = 1/2 + √ 9/4 Since a square root has two values, one positive and the other negative r 2 - r - 2 = 0 has two solutions: r = 1/2 + √ 9/4 or r = 1/2 - √ 9/4