Question

Sum of all natural numbers between 100 and 300 excluding both of these are exactly divisible by 5

Answer 1

Step-by-step explanation:

hope it helps u

Answer 2

Answer:

All those numbers between 100 to 300 which are divisible by 5 are, 105, 110, 115, …. 295.

As this is a sequence of a fixed difference between the consecutive terms, also called as an arithmetic progession (A.P.).

Sum of this sequence =105+110+115+...295=105+110+115+...295

For given A.P., we have

First terms, a = 105

Common difference, d = 5

Last term, anan = 295

No. of terms, n = 39.

Sum =n(a+an)2.=n(a+an)2.

Putting values of a, anan, and n, we have

Sum =39(105+295)2=39(105+295)2

Sum = 7800.

Hope it helps you !