Question

Radhika's age was half as Suhas age if the ratio of the present ages is 3 is to 4 what will be the sum of their present ages

Answer 1

HEY MATE
$\huge\mathfrak\red{Solution}$
$<b>$
10 years later
Let the Radhika's age be x

suhas age will be 2x

Their present age will be
Radhika's - x+10
suhas - 2x+10
age ratio =
(x+10)/(2x+10)=3/4
by cross multiplication
4x+40=6x+30
6x-4x=40-30
2x=10
x=5
Radhika's present age
=5+10=15
Suhas's present age=2*5+10 =20
Sum of their ages=15+20 =35

$<I><u><b>$
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Answer 2

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