radiations of two different frequencies whose photon energies are 3.4v and 8.2v successively illuminate a metal surface whose work function is 1.8v. the ratio of the maximum speeds of the emitted electrons will be?
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Answer:
Its actually 1:2
Explanation:
Because the Einsteins photoelectric equation is e=w+k
u have give the e to be 3.4 and 8.2 and w o be 1.8
as the k is kinetic energy of the photon .
with the given equation you will be able to compare the kinetic energies as the mass of photon is equal you can cancel the mass and the v^2 will remain with the right being 1:4 and then you take the square root you will get the mentioned answer 1:2.
that is 3.4-1.8=1.6
and 8.2-1.8=6.4
so 1.6/6.4=1/4 now the
v1^2/v2^2=1/4 now
v1/v2=1/2
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