Question

Radius of current carrying coil is 'R'. Then ratio
of magnetic fields at the centre of the coil to the
axial point, which is R 13 distance away from the
centre of the coil :-
(1) 1 : 1
(2) 1 : 2
(3) 1:4
(4) 8:1​

Answer 1

Answer:

8:1

Explanation:

$b_{c} = \frac{m_{a}i}{2r}$

$b_ axial = \: \frac{ m_{0}({ir}^{2} ) }{ {2r}^{3} {(4)}^{ \frac{3}{2} } }$

so,

$\frac{b_{c}}{ b_ axial} = \frac{8}{1}$

hope it will help you......

Answer 2

Answer:

it's 4 option................