↵Rahul purchased every year national saving certificates of value exceeding the last year purchase by Rs.500. After 6 years, he finds the total value of the 500 certificates purchased by him is Rs.13500. Find the value of the certificates purchased:(i)In the first year (ii)In the fifthyear
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Solution:-
Common difference = Rs. 500
S₆ = Rs. 13500
Sn = n/2{2a + (n - 1)d}
13500 = 6/2{2a + (6 - 1)500}
13500/3 = 2a + (5*500)
4500 = 2a + 2500
2a = 4500 - 2500
2a = 2000
a = 1000
So, the value of the certificates purchased in the first year is Rs. 1000
a = 1000, d = 500
The required A.P is 1000, 1500, 2000, 2500, 3000, 3500 .......
So, the value of the certificates purchased in the 5th year is Rs. 3000
Answer.
Common difference = Rs. 500
S₆ = Rs. 13500
Sn = n/2{2a + (n - 1)d}
13500 = 6/2{2a + (6 - 1)500}
13500/3 = 2a + (5*500)
4500 = 2a + 2500
2a = 4500 - 2500
2a = 2000
a = 1000
So, the value of the certificates purchased in the first year is Rs. 1000
a = 1000, d = 500
The required A.P is 1000, 1500, 2000, 2500, 3000, 3500 .......
So, the value of the certificates purchased in the 5th year is Rs. 3000
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