Math, asked by sajopster111, 11 months ago

raju father is 25year olderthanrajuafter 10 year fathers age willbe double that of rajus find their present age.?​

Answers

Answered by Anonymous
3

Step-by-step explanation:

Let, the present age of raju is=x years

And his father's age be=(x+25)years

Now after 10 years raju's father age will be twice as raju,,

So according to the problem..

x+25+10=2*(x+10)

=>x+35=2x+20

=>35-20=2x-x

=>x=15

Therefore presentage of raju=15 years

And present age of his father=15+25=40years

Answered by Anonymous
13

\bold{\Huge{\underline{\boxed{\rm{\red{ANSWER\::}}}}}}

Given:

Raju's father is 25 year older than Raju after 10 years father age will be double that of Raju.

To find:

Their present ages.

\bold{{\Large{\underline{\sf{\green{Explanation\::}}}}}}

Let the Raju age be R years &

Let the Raju's father be (R+25) years

  • After 10 years;

The age of Raju = 2(R+10) years

The age of Raju's father = (R+25)+10 years

A/q

→ 2(R+10) = (R+25)+10

→ 2R + 20 = R+ 25+ 10

→ 2R + 20 = R+ 35

→ 2R - R = 35 - 20

→ R = 15 years.

Thus,

The present age of Raju is 15 years &

The present age of Raju's father is (15+25) years= 40 years.

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