raju father is 25year olderthanrajuafter 10 year fathers age willbe double that of rajus find their present age.?
Answers
Step-by-step explanation:
Let, the present age of raju is=x years
And his father's age be=(x+25)years
Now after 10 years raju's father age will be twice as raju,,
So according to the problem..
x+25+10=2*(x+10)
=>x+35=2x+20
=>35-20=2x-x
=>x=15
Therefore presentage of raju=15 years
And present age of his father=15+25=40years
Given:
Raju's father is 25 year older than Raju after 10 years father age will be double that of Raju.
To find:
Their present ages.
Let the Raju age be R years &
Let the Raju's father be (R+25) years
- After 10 years;
The age of Raju = 2(R+10) years
The age of Raju's father = (R+25)+10 years
A/q
→ 2(R+10) = (R+25)+10
→ 2R + 20 = R+ 25+ 10
→ 2R + 20 = R+ 35
→ 2R - R = 35 - 20
→ R = 15 years.
Thus,
The present age of Raju is 15 years &
The present age of Raju's father is (15+25) years= 40 years.