Math, asked by gurmejsinghdeol, 1 year ago

Raju takes 4 hours more than raju to cover a distance of 40 km. if raju doubles his speed, he takes 3/2 hours more than ajay to cover the same distance. find the speed of both.

Answers

Answered by drushasangwan
10

Answer:

Step-by-step explanation:

The solution is in pic

Attachments:
Answered by aquialaska
8

Answer:

Speed of Raju is 8 km/hr and Speed of Ajay is 40 km/hr.

Step-by-step explanation:

let the speed of Raju = x km/hr

    the speed of Ajay = y km/hr

According to the question,

40/x - 40/y = 4 ..........................(1)

40/2x - 40/y = 3/2 ......................(2)

put 1/x = u and 1/y = v in (1) & (2)

we get

40u - 40 v = 4

20u - 40v = 3/2

40u - 40v = 4 ........................(3)

40u - 80v = 3 ..........................(4)

Subtract (4) from (3),

-40v  - ( -80v ) = 4 - 3

-40v + 80v = 1

40v = 1

v = 1/40

put this in (3), we get

40u - 40(1/40) = 4

40u - 1 = 4

40u = 5

u = 5/40

u = 1/8

Now, 1/x = u ⇒ 1/x = 1/8 ⇒ x = 8

1/y = v ⇒ 1/y = 1/40 ⇒ y = 40

Therefore, Speed of Raju is 8 km/hr and Speed of Ajay is 40 km/hr.

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