Ram and shyam are standing at two ends of a room with a width of 30 m. They start walking towards each other along the width of the room with a speed of 2 m/s and 1 m/s respectively. Find the total distance traveled by ram when he
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2 meter per second round of applause in motion
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Given :
Width of the room = 30 m =
Speed of ram = 2 m/s
Speed of shyam = 1 m/s
To find :
The total distance traveled by ram when he and shyam was at same position.
Solution :
• Concept used here is that time taken to reach that position will be equal for both ram and shyam
• Let us assume distance travel by ram is x m and therefore
Distance traveled by shyam = 30 - x m
• We know that,
Speed = distance / time
• For ram,
2 m/s = x m / t s
t = x/2
• For shyam,
1 m/s = 30 - x / t s
t = 30 - x / 1
Equating both t values
x/2 = 30 - x
x = 60 - 2x
3x = 60
x = 20 m
• Hence, the total distance traveled by ram when he and shyam was at same position is 20 m
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