Ramesh scored 30% marks and failed by 20 marks while Suresh scored 40% marks and got 40 marks more than the minimum marks required to pass the exam find the maximum marks and pass percent?..
...please answer immediately.... with steps
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Let the total marks be x.
Then (30% of x) + 20 = (40% of x) - 40 ---- (1)
30/100 x + 20 = 40/100 x - 40
1/10 x = 60
x = 600.
Therefore, (30% of 600) + 20 = (30/100 * 600 + 20)
= 200.
Pass % = (200/600 * 100)%
= 33.3 (or)33 1/3.
Hope this helps! :)
Then (30% of x) + 20 = (40% of x) - 40 ---- (1)
30/100 x + 20 = 40/100 x - 40
1/10 x = 60
x = 600.
Therefore, (30% of 600) + 20 = (30/100 * 600 + 20)
= 200.
Pass % = (200/600 * 100)%
= 33.3 (or)33 1/3.
Hope this helps! :)
TanmayB16:
thx
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