Ramya Said the length of tangent of a circle with centre'O' from a point 'P' which is out side of the circle is always less than 'OP'. Do you agree? give reasons
Answers
Answered by
59
Answer:
Step-by-step explanation:
Given: p is the external point ,
AP is the tangent
O is joint with P
RTP: AP<OP
Construction: Join O and P
Solution : In ∆AOP
Through Pythagoras theorem we can say that hypotenuse is the longest side.
Therefore, AP<OP
Answered by
1
Ramya's statement is true.
Step-by-step explanation:
Given:
P is outside the circle
and
AP is the tangent (tangent always forms a right angle along the radius).
Construction:
Join O and P
In ∆AOP
AP is parpedicular
AO is base
and OP is hypotenuse
Therefore, AP<OP
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