Question

Rate constant of a reaction with a virus is 3.3 10 to power minus 4 time required for the virus to become 75% in activated is

Answer 1

Answer:

Explanation:

=> Here It is given that,

Rate constant of a reaction with a virus, k = 3.3 * 10⁻⁴

Time required for the virus to become 75% inactivated, t = ?

=> when 75% of the virus in inactivated, then the fraction:

[A]/[A⁰]= 0.25

t= 2.303 log [A]/[A⁰] / k

∴ t=2.303 log (0.25) /3.3×10⁻⁴

=4.2×10³ s

= 70 min (or 1 hour 10 mins)

Thus, the time required for the virus to become 75% inactivated is 70 min.