Question

Red flag, 3 white flags and 2 blue flags are arranged in a line such that: i. No two adjacent flags are of the same colour ii. The flags at the ends are of 2 different colours. In how many different ways the flags be arranged?

Answer 1

Answer:5 different flags so we can make flag by

2flags=5x4=20

3flags=5x4x3=60

4flags=5x4x3x2=120

5flags=5x4x3x2x1=120 ways

so the number of ways to make different signs is 120+120+60+20=320 ways

Step-by-step explanation: