Physics, asked by KishoreRishwanth, 4 months ago

Rate of heat flow through a cylindrical rod is Qı:
Temperatures of ends of rod are T, and Tg. If all the
linear dimensions of the rod become four times and
temperature difference remains same, it's rate of
heat flow is Qą, then :-
(1) Q2 = 2Q2
(2) Q2 = 2Q,
(3) Q, = 4Q
(4) Q, = 4Q2​

Answers

Answered by sanvi01vyas
3

Answer:

Rate of heat flow through a cylindrical rod is Qı:

Temperatures of ends of rod are T, and Tg. If all the

linear dimensions of the rod become four times and

temperature difference remains same, it's rate of

heat flow is Qą, then :-

(1) Q2 = 2Q2

(2) Q2 = 2Q,

(3) Q, = 4Q

(4) Q, = 4Q2

Then the answer is 2)

Answered by Anonymous
2

Correct Question

Rate of heat flow through cylindrical rod is Q¹

Temperatures of ends of rod are T¹

and T² . If all the linear dimensions of the rod become double and temperature difference remains same, its rate of heat flow is Q² then .

Correct Option

Q2 = 2Q1

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