Ratio of ages of three person is 4 7 9 eight years ago the sum of their ages was 56 find thire present age
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Answer:
Step-by-step explanation:present ages are 4x,7x,9x
sum of ages are 8 years ago (4x-8)+(7x-8)+(9x-8)=56
20x=80
x=4
so the present ages are 16,28,36
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the ratio of three people's ages are=4x, 7x, 9x.
the ratio of their present age are=4x+8, 7x+8, 9x+8.
so, 4x+8+7x+8+9x+8=56+8
20x+24=56+8
20x=64-24
20x=40
x=40/20
x=2
so, 4x+8=4×2+8=16
7x+8=7×2+8=22
9x+8=9×2+8=26
the ratio of their present age are=4x+8, 7x+8, 9x+8.
so, 4x+8+7x+8+9x+8=56+8
20x+24=56+8
20x=64-24
20x=40
x=40/20
x=2
so, 4x+8=4×2+8=16
7x+8=7×2+8=22
9x+8=9×2+8=26
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