Question

ratio of sum of n terms of two ap is 6n - 5 ratio 4n+ 3 find the ratio of their m terms​

Answer 1

Answer:

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Answer 2

=(n/2(2a1 +(n-1)d1))/(n/2(2a2 +(n-1)d2))=(6n-5)/(4n+3)

=(2a1 +(n-1)d1)/(2a2 +(n-1)d2)=(6n-5)/(4n+3)

=(a1 +((n-1)/2)d1)/(a2 +((n-1)/2)d2))=(6n-5)/(4n+3) --- eq1

=(n-1)/2=m-1

=n-1=2m-2

=n=2m-1 ---eq2

Put eq2 in eq 1

=(a1+(m-1)d1)/(a2+(m-1)d2)=(6(2m-1)-5)/(4(2m-1)+3)

=Tn1/Tn2=(12m-11)/(8m-1)