'Rational numbers are commutative under addition but not commutative under subtraction.' Justify the statement with an ex.
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Commutative property of Rational numbers states that , if there are two rational numbers 'a' and 'b' .
Then , a+b = b+a
Let's, verify it -
let a be 5
let b be 6
So, a+b = b+a
5+6 = 6+5
11 = 11
Hence , LHS = RHS
So, Rational numbers are commutative under addition.
But Can we say so for Subtraction?
→ If Rationals are commutative under substraction , then -
a-b = b-a
Let , a be 5
let b be 6
So, 5-6 = 5-6
- 1 ≠ 1
Hence , LHS ≠ RHS
So, Rationals aren't commutative under substraction.
Then , a+b = b+a
Let's, verify it -
let a be 5
let b be 6
So, a+b = b+a
5+6 = 6+5
11 = 11
Hence , LHS = RHS
So, Rational numbers are commutative under addition.
But Can we say so for Subtraction?
→ If Rationals are commutative under substraction , then -
a-b = b-a
Let , a be 5
let b be 6
So, 5-6 = 5-6
- 1 ≠ 1
Hence , LHS ≠ RHS
So, Rationals aren't commutative under substraction.
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