Question

rationalisation 3√3 upon 2+√3.​

Answer 1

Answer:

$\frac{3 \sqrt{3} }{2 + \sqrt{3} } \\ = \frac{3 \sqrt{3} \times (2 - \sqrt{3}) }{(2 + \sqrt{3} ) \times (2 - \sqrt{3} )} \\ = \frac{6 \sqrt{3 } - 9}{4 - 3} \\ = 6 \sqrt{3} - 9$

Step-by-step explanation:

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