Question

rationalise the denominator 7-4√3/7+4√3​

Answer 1

Answer:

@user died...........

Answer 2

Answer:

$\frac{7 - 4 \sqrt{3} }{7 + 4 \sqrt{3} } \\ \\ rationaizing \: factor \: = \\ \frac{1}{7 - 4 \sqrt{3} } \\ \\ \frac{7 - 4 \sqrt{3} }{7 + 4 \sqrt{3} } \times \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} } \\ \\ \frac{(7 - 4 \sqrt{3)^{2} } }{7 {}^{2} - (4 \sqrt{3) {}^{2} } } \\ \\ \frac{49 + 48 - 2 \times 7 \times 4 \sqrt{3} }{49 - 48} \\ \\ \frac{97 - 14 \times 4 \sqrt{3} }{1} \\ \\ = 83 \sqrt{3}$

Hope it helps