Question

Rationalise the denominator of 1/[7+3root3]

Answer 1

Answer:

$\frac{1}{7 + 3 \sqrt{3} } \times \frac{7 - 3 \sqrt{3} }{7 - 3 \sqrt{3} } = \frac{7 - 3 \sqrt{3} }{49 - 9} = \frac{7 - 3 \sqrt{3} }{40}$

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