Question

Rationalize 1/2-undroot3

Answer 1

$\bf \frac{1}{2-\sqrt{3}}\times\frac{2+\sqrt{3}}{2+\sqrt{3}}\\\\\\= \frac{2+\sqrt{3}}{(2)^{2}-(\sqrt{3})^{2}}\\\\\\=\frac{2+\sqrt{3}}{4-3}\\\\\\=\frac{2+\sqrt{3}}{1}\\\\\\= 2+\sqrt{3}$

Answer 2

Answer:

$\frac{1}{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} }$

$= \frac{2 + \sqrt{3} }{ {2}^{2} - { \sqrt{3} }^{2} }$

$= \frac{2 + \sqrt{3} }{4 - 3}$

$= \frac{2 + \sqrt{3} }{1}$

$= 2 + \sqrt{3}$

$\huge \orange{note : - }$

$\huge (x + y)(x - y) =$

$\huge \: ( {x})^{2} - ({y})^{2}$

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