Question

rationalize the denominator 1/ √8 + 4√3

Answer 1

Answer:

❣ ANSWER ❣

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$\frac{1}{ \sqrt{8} + 4 \sqrt{ 3} } \\ = \frac{1( \sqrt{8} - 4 \sqrt{3} )}{( \sqrt{8} + 4 \sqrt{3} )( \sqrt{8} - 4 \sqrt{3}) } \\ = \frac{ \sqrt{8} - 4 \sqrt{3} }{8 - 12} \\ = \frac{2 \sqrt{3} - 4 \sqrt{ 3} }{ - 4} \\ = \frac{-2 \sqrt{ 3} }{ - 4} \\ = \frac{ \sqrt{ 3} }{ 2}$

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