Question

Rationalize the denominator 19/3√3+2√2
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Answer 1

Step-by-step explanation:

we have,

$\qquad \qquad\dfrac{19}{3\sqrt{3}+2\sqrt{2}}$

$\qquad \quad \implies\dfrac{19}{3\sqrt{3}+2\sqrt{2}}×\dfrac{3\sqrt{3}-2\sqrt{2}}{3\sqrt{3}-2\sqrt{2}}$

$\qquad \quad \implies\dfrac{19(3\sqrt{3}-2\sqrt{2})}{(3\sqrt{3})^2-(2\sqrt{2})^2}$

$\qquad \quad \implies\dfrac{57\sqrt{3}-38\sqrt{2}}{27-8}$

$\qquad \quad \implies\dfrac{57\sqrt{3}-38\sqrt{2}}{19}$