Chemistry, asked by Anonymous, 8 months ago

rationalize the denominator

√2-√3/√2+√3​

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Answered by Anonymous
2

Answer:

hope this helps you dear

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Answered by Anonymous
2

Hii sanju

 =  \frac{ \sqrt{2}  -  \sqrt{3} }{ \sqrt{2}  +  \sqrt{3} }  \\

rationalize the denominator

 =  \frac{ \sqrt{2}  -  \sqrt{3} }{ \sqrt{2}  +  \sqrt{3} }  \times  \frac{ \sqrt{2}   -  \sqrt{3} }{ \sqrt{2}  -  \sqrt{3} }  \\

 =  \frac{ {( \sqrt{2}  -  \sqrt{3} })^{2} }{2 - 3}  \\

 =  \frac{ {( \sqrt{2} })^{2}  -  2 \sqrt{6}   +  \sqrt{6}  ^{2} }{ - 1}  \\

 =  \frac{2 - 2 \sqrt{6} + 6 }{ - 1}  \\

 = \frac{8 - 2 \sqrt{6}  }{ - 1}  \\

 = 2 \sqrt{6}  - 8 \\

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