Math, asked by navajish6, 7 months ago

rationalize the denominator
3÷(root5-root7)

Answers

Answered by Anonymous
5

\frac{3}{\sqrt{5}-\sqrt{7}  } \\\\= \frac{3 ( \sqrt{5}+\sqrt{7} )  }{\sqrt{5}-\sqrt{7}  ( \sqrt{5}+\sqrt{7} )  } \\\\\\= \frac{3\sqrt{5} + 3\sqrt{7} }{5-7} \\\\=  \frac{3\sqrt{5} + 3\sqrt{7} }{-2} \\\\\\=  \frac{-3\sqrt{5} - 3\sqrt{7} }{2} \\

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