Question

rationalize the denominator 5 by root 3 minus root 5

Answer 1

It is done as shown above.

Hope it helps! :)

Answer 2

Answer:

$\frac{5}{(\sqrt{3}-\sqrt{5})}$ =$\frac{5(\sqrt{3}-\sqrt{5})}{-2}$

Explanation:

Given $\frac{5}{(\sqrt{3}-\sqrt{5})}$

Rationalising the denominator, we get

=$\frac{5(\sqrt{3}-\sqrt{5})}{(\sqrt{3}-\sqrt{5})(\sqrt{3}+\sqrt{5})}$

=$\frac{5(\sqrt{3}-\sqrt{5})}{(\sqrt{3})^{2}-(\sqrt{5})^{2}}$

=$\frac{5(\sqrt{3}-\sqrt{5})}{3-5}$

= $\frac{5(\sqrt{3}-\sqrt{5})}{-2}$

Therefore,

$\frac{5}{(\sqrt{3}-\sqrt{5})}$ =$\frac{5(\sqrt{3}-\sqrt{5})}{-2}$

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