Math, asked by yashikamota, 7 months ago


Rationalize the denominator in the following 1/√7-√6 ​

Answers

Answered by devesh48ravi
1

So let's solve:-

 \frac{1}{ \sqrt{7} -  \sqrt{6}  }   \\ \frac{1}{ \sqrt{7} -  \sqrt{6}  }    \times \frac{ \sqrt{7} +  \sqrt{6}  }{ \sqrt{7}  + \sqrt{6}  }    \\ \frac{ \sqrt{7} +  \sqrt{6}  }{ (\sqrt{7}   -  \sqrt{6})   \times(\sqrt{7}    + \sqrt{6})}    \\   \frac{ \sqrt{7} +  \sqrt{6}  }{7 - 6}  \\ \frac{ \sqrt{7} +  \sqrt{6}  }{1}

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