Math, asked by ap6570215, 9 months ago

rationalize the denominator of 1 upon root 9 - root 8 ​

Answers

Answered by aditi11o4
2
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Answered by UniqueBrain16
3

Answer:-

\frac{1}{\sqrt{9}-\sqrt{8}  }

\frac{1}{\sqrt{9}-\sqrt{8}}  ×  \frac{\sqrt{9}+\sqrt{8}  }{\sqrt{9}+\sqrt{8}  }

\frac{\sqrt{9} + \sqrt{8}  }{9 - 8}

\frac{\sqrt{9} + \sqrt{8}   }{1}

\sqrt{9} + \sqrt{8}

⇒ 3 + \sqrt{8}

Hence the denominator is Rationalized.

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