Question

Rationalize the dinominator 3/√7 - √2

Answer 1

Answer:

$\frac{3}{ \sqrt{7} - \sqrt{2} } \\ = \frac{3}{ \sqrt{7} - \sqrt{2} } \times \frac{\sqrt{7} + \sqrt{2}}{\sqrt{7} + \sqrt{2}} \: \\ = \frac{3( \sqrt{7} + \sqrt{2}) }{( { \sqrt{7}) }^{2} - ( { \sqrt{2}) }^{2}} \\ = \frac{3( \sqrt{7} + \sqrt{2}) }{7 - 2} \\ = \frac{3( \sqrt{7} + \sqrt{2}) }{5}$