rationalize where x=5+2root5 y=1/x find x2 + y2
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Given that, x = 5+2√5 and
y = 1 / x
= 1 / 5+2√5
= 1 / 5 + 2√5 × 5–2√5 / 5–2√5
= 5–2√5 / ( 5² –2√5² )
= 5 –2√5 / ( 25 – 20 )
= 5 – 2√5 / 5
Now, x² + y²
= ( 5+2√5 )² + ( 5 – 2√5 / 5 )²
= ( 25 + 20 + 20√5 ) + [ ( 25 + 20 – 20√5 ) / 25 ]
= ( 45 + 20√5 ) + [ ( 45 – 20√5 ) / 25 ]
= 5 ( 9 + 4√5 ) + 5 ( 9 – 4√5 ) / 25
= 5 ( 9 + 4√5 ) + ( 9 – 4√5 ) / 5
= [ 25 ( 9 + 4√5 ) + ( 9 – 4√5 ) ] / 5
= ( 225 + 100√5 + 9 – 4√5 ) / 5
= ( 216 + 96√5 ) / 5
= 24 ( 9 + 4√5 ) / 5
Given that, x = 5+2√5 and
y = 1 / x
= 1 / 5+2√5
= 1 / 5 + 2√5 × 5–2√5 / 5–2√5
= 5–2√5 / ( 5² –2√5² )
= 5 –2√5 / ( 25 – 20 )
= 5 – 2√5 / 5
Now, x² + y²
= ( 5+2√5 )² + ( 5 – 2√5 / 5 )²
= ( 25 + 20 + 20√5 ) + [ ( 25 + 20 – 20√5 ) / 25 ]
= ( 45 + 20√5 ) + [ ( 45 – 20√5 ) / 25 ]
= 5 ( 9 + 4√5 ) + 5 ( 9 – 4√5 ) / 25
= 5 ( 9 + 4√5 ) + ( 9 – 4√5 ) / 5
= [ 25 ( 9 + 4√5 ) + ( 9 – 4√5 ) ] / 5
= ( 225 + 100√5 + 9 – 4√5 ) / 5
= ( 216 + 96√5 ) / 5
= 24 ( 9 + 4√5 ) / 5
gauravreddy:
thanks
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