Question

rationlize the denominator √6/√3-√2​

Answer 1

HERE'S YOUR ANSWER

$\frac{ \sqrt{6} }{ \sqrt{3} - \sqrt{2} } = \frac{ \sqrt{6} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ = \frac{ \sqrt{18} + \sqrt{12} }{3 - 2} = \sqrt{18 } + \sqrt{12}$