Question

Ravi ate 2/7 part of a cake while his sister ate 4/5 of remaining. part of the cake left is.....

Answer 1

Answer:

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Step-by-step explanation:

$\boxed{ \bigstar{ \mathcal{ \huge{ \pink{answer....}}}}}$

$\green{ \bold{\: let \: the \: entire \: cake \: be \: x}} \\ ravi \: has \: eaten.. = \frac{2x}{7} \\ leftover \: cake = x - \frac{2x}{7} = \frac{5x}{7} \\ her \: sister \: has \: eaten \: \: \frac{4}{5} th \: of \: leftover \\ = > \frac{4}{5} \times \frac{5x}{7} = \frac{4x}{7} \\ so \: total \: cake \: eaten = \frac{2x}{7} + \frac{4x}{7} = \frac{6x}{7} \\ \: leftover \: cake = x - \frac{6x}{7} = \frac{x}{7} \\ \bold{ \green{ \: so \: only \: \frac{1}{7} th \: is \: left \: out}}$

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Answer 2

Step-by-step explanation:

Let the whole cake be x.

Ravi ate 2x/7 and his sister ate 4/5 of the remaining cake.

Remaining part = x - 2x/7 = 5x/7

(since remaining part = whole - eaten part)

Sister ate = 4/5 of the remaining part which is 5x/7 as we found above,

Therefore 4/5*5x/7 = 4x/7

Total eaten part = 2x/7+4x/7 =6x/7

Remaining part = x - 6x/7 = 7x/7 - 6x/7

= 1x/7

Therefore, 1/7 part is left