Ravi was asked to solve the following "Hcf and lcm of two no.'s is 50and 275 resp.if one.
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Gita is right question is wrong because if hcf is 50 then 125 should be fully divisible by 50
Rishav2408:
but 125 is not divisible by hcf thats why it is wrong question
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Answered by
8
HI !
The question is wrong actually.
We know that HCF of 2 no:s is always a factor of its LCM .
HCF and LCM of two no:s must be exactly divisible by each other.
But 275 is not divisible by 50 .
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Also, we can prove that the given no:s(HCF and LCM) are wrong :-
HCF*LCM = product of 2 no:s
275*50 = 125*x
13750 = 125x
x = 13750/125
x = 110
if the no:s are 110 and 125 ,
their hcf = 5
and lcm = 2750
Hence. the question is wrong.
The question is wrong actually.
We know that HCF of 2 no:s is always a factor of its LCM .
HCF and LCM of two no:s must be exactly divisible by each other.
But 275 is not divisible by 50 .
-------------------------------------------------------------------------------
Also, we can prove that the given no:s(HCF and LCM) are wrong :-
HCF*LCM = product of 2 no:s
275*50 = 125*x
13750 = 125x
x = 13750/125
x = 110
if the no:s are 110 and 125 ,
their hcf = 5
and lcm = 2750
Hence. the question is wrong.
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