Question

Read the following and answer questions.
Oxygen is prepared by catalytic decomposition of potassium chlorate (KCIO). Decomposition of potassium chlorate gives potassium chloride (KCI) and oxygen (0.). The following reaction takes place: KCIO, (s)-KC1(s) +0,(g)


1 How many moles of KCIO, are required to produce 2.4 moles of 0,7

2 Which element is reduced in the given reaction.

3 How many moles of KCIO, give 3 moles of oxygen?

4 The oxidation state of chlorine in potassium chlorate is

5 Decomposition of potassium chlorate gives
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Answer 1

Answer:

Decomposition of KClO

3

takes place as:

2KClO

3

(s)→2KCl(s)+3O

2

(g)

2 mole of KClO

3

=3 mole of O

2

∵ 3 mole O

2

formed by 2 mole KClO

3

∴2.4 mole of O

2

will be formed by:

(

3

2

×2.4) mol KClO

3

= 1.6 mole of KClO

3

.

Mass of KClO

3

= Number of moles × Molar mass

=1.6×122.5=196g