Question

Reading of an ideal voltmeter in the circuit below is

Answer 1

When current dosen't pass across an ideal voltmeter remove it for sometime.  

Joined resistance of both resistors is 4 ohm + 6 ohm = 10 ohm.  

Voltage on both resistors is either 6 volts or 18 volts.  

Formerly current is 6V/10ohm=0.6A .  

0.6 ampere current causes a voltage drop of 3.6V on the larger resistor and 2.4V on the smaller resistor hence voltmeter reading will be 6+2.4 = 12-3.6 = 8.4 volts.  

When current is triple then voltage drop is also triple

7.2V on smaller resistor and 10.8V on larger resistor and reading is 7.2-6 = 12-10.8 = 1.2 volts.

Answer 2

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