Question

Reasoning Type:

Statement 1: If √7x²-6x-13√7=0, then x = 13√7/7,-√7
statement 2: if ax²+bx+c=0;a,b,c belongs to Ra≠0 then x=-b+-√b²-4ac/2a
1) Both statements are true
2) Both statements are false
3) Statement I is true statement II is false
4) Statement I is false, statement II is true​

Answer 1

Answer:

$</p><p>7x2−6x−137=0 \\ </p><p></p><p></p><p>7x−6x−137=0 \\ </p><p></p><p></p><p>(7−6)x=137 \\ </p><p></p><p></p><p>x=7−6137 \\ </p><p></p><p>$