Reciprocal of (-5/11) x (33/15) is
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Answer:
Letx=
11
5
andy=
55
−15
\begin{gathered} Product \:of \: x \: and \: Reciprocal \:of \:y \\= \frac{5}{11} \times \frac{-55}{15} \\= \frac{- 5 \times 5 \times 11}{ 11 \times 3 \times 5 } \end{gathered}
ProductofxandReciprocalofy
=
11
5
×
15
−55
=
11×3×5
−5×5×11
/* After cancellation, we get */
= \frac{ -5}{3}=
3
−5
Therefore.,
\red{Required \: product}\green {=\frac{ -5}{3}}Requiredproduct=
3
−5
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