Question

rectangular piece of paper as area of 24 cm square and length is equal to 5 cm find its perimeter
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Answer 1

Given :-

The area of rectangular piece of paper = 24 cm square.

The length is = 5 cm

Now,

breadth = ? [not given]

We can find the breadth by the formula of area of the rectangle

So,

Area of the rectangle = lb unit square

[ ∴ In which l is the length and b is the breadth of the rectangle ]

So,

⇒ 24 = lb

⇒ 24 = 5 × b   [value of l = 5cm]

⇒ 24 ÷ 5 = b   [transporting 5 to LHS]

⇒ 4.8 = b

∴ breadth (b) = 4.8 cm

Now

To be found :-

The perimeter of the rectangle

   

The formula for finding the perimeter of rectangle = 2(l+b) units

[∴ In which l is the length and b is the breadth of the rectangle]

Perimeter of rectangle = 2(5 + 4.8)

                                      = 2(9.8)

                                      = 19.6 cm

Hence,

the perimeter of the rectangular piece of paper is 19.6 cm

Answer 2

The area of rectangular sheet of paper is given = 24 cm^2

length = 5 cm

we need to find breadth = ?

Area of the rectangle = lenght × breadth

lenght = l & breadth = b

therefore,

⇒ 24 = lb

⇒ 24 = 5 × b  

⇒ 24 ÷ 5 = b  

⇒ 4.8 = b

breadth (b) = 4.8 cm

The perimeter of the rectangle  

the perimeter of rectangle = 2(l+b)

Perimeter of rectangle = 2(5 + 4.8)

                                      = 2(9.8)

                                      = 19.6 cm

therefore,

we get =

the perimeter of the rectangular piece of paper is 19.6 cm