Question

Reena is twice as old as sunita. Three years ago, she was three times as old as sunita. How old is reena now? A) 6 years b) 7 years c) 8 years d) 12 years

Answer 1

Let Sunita's age be x years.

Reena's age = 2 x years.

3 years ago,

Sunita's age = (x-3) years

Reena's age = ( 2 x - 3 ) years

A/Q, 3(x-3) = 2 x - 3

⇒ 3 x - 9 = 2 x - 3

so

x = 6

Reena's age = 6 x 2 = 12 years.

Answer 2

$<b>Heya mate. (^_-). Solution below.$
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[] At present,

Let Sunita's age be 'x'.

Reena's age = 2x



[] Three years ago from now,

Sunita's age = x - 3

Reena's age = 2x - 3




[] But, according to the question, Reena was thrice as old as Sunita.

=>> 2x - 3 = 3 (x - 3)

=> 2x - 3 = 3x - 9

=> -3 + 9 = 3x - 2x

=> 6 = x


So, Sunita's present age = x = 6 years.

And, Reena's present age = 2x = 2 × 6 = 12 years.


•°• Reena is 12 years old at present (option D).
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$<marquee>Thank you and Happy Diwali. (^_-). </marquee>$